1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
249
250
251
252
253
254
255
256
257
258
259
260
261
262
263
264
265
266
267
268
269
270
271
272
273
274
275
276
277
278
279
280
281
282
283
284
285
286
287
288
|
subroutine dbasin(ierr,lunit,fmt,v,iv,n)
c ====================================================================
c
c gestion de la standard input
c
c ================================== ( Inria ) =============
c
c Copyright INRIA
include '../stack.h'
character*(*) fmt
double precision v(*)
integer ierr,lunit
character*512 string
c
ierr=0
if(lunit.eq.rte) then
string=' '
call xscion(iflag)
if (iflag.eq.0) then
call zzledt(string,len(string),lline,status)
else
call zzledt1(string,len(string),lline,status)
endif
if(status.ne.0) goto 10
if (lline.eq.0) then
string(1:1)=' '
lline=1
endif
if(fmt(1:1).ne.'*') then
read(string(1:lline),fmt,end=10,err=20) (v(i),i=1,n*iv,iv)
else
call s2val(string(1:lline),v,iv,n1,n,ierr)
if(ierr.ne.0) goto 20
if(n1.lt.n) goto 10
c read(string(1:lline),*,end=10,err=20) (v(i),i=1,n*iv,iv)
endif
else
if(fmt(1:1).ne.'*') then
read(lunit,fmt,end=10,err=20) (v(i),i=1,n*iv,iv)
else
read(lunit,*,end=10,err=20) (v(i),i=1,n*iv,iv)
endif
endif
c
return
c
10 ierr=1
return
20 ierr=2
return
end
subroutine s2val(str,v,iv,n,maxv,ierr)
c!purpose
c internal "list-directed" read mode is not standard fortran.
c This routine emulates :read(str,*) (v(1,i),i=1,n)
c!
double precision v(iv,maxv),vv
character*(*) str
character*1 si
logical del
c
ls=len(str)
del=.true.
c
ierr=0
n0=n
n=0
i=0
10 i=i+1
c loop on decriptors
if(i.gt.ls) goto 20
si=str(i:i)
if(si.eq.'/'.or.si.eq.',') then
if(del) then
if(n+1.gt.maxv) return
v(1,n+1)=0.0d0
n=n+1
goto 10
else
del=.true.
endif
endif
if(si.ne.' '.and.si.ne.'/'.and.si.ne.',') then
c conversion of a descriptor to a (repeated) value
call nextv(str(i:),vv,nv,ir,ierr)
if(ierr.ne.0) return
if(n+nv.gt.maxv) nv=maxv-n
if(nv.le.0) return
call dset(nv,vv,v(1,n+1),iv)
n=n+nv
i=i+ir-2
del=.false.
endif
goto 10
20 continue
if(del) then
if(n+1.gt.maxv) return
v(1,n+1)=0.0d0
n=n+1
endif
return
end
subroutine nextv(str,v,nv,ir,ierr)
c acquisition d'un nombre flottant decrit par une chaine
c de caracteres de la forme
c [nn*][+|-][mmmmm][.][ddd][e|E|d|D[+|-]eee]
character*(*) str
character*1 next
double precision v
integer c(4)
integer sgn,expsgn
ls=len(str)
c(1)=0
c(2)=0
c(3)=0
c(4)=0
sgn=1
nv=1
i=1
ic=0
if(str(i:i).eq.'-') then
sgn=-1
i=i+1
elseif(str(i:i).eq.'+') then
sgn=1
i=i+1
else
sgn=1
endif
10 if(i.gt.ls) goto 20
call s2int(str(i:),nlz,iv,ir,ierr)
if(ierr.ne.0) iv=0
i1=i-1+ir
if(i1.le.ls) then
next=str(i1:i1)
if (next.eq.'e'.or.next.eq.'E'.or.
$ next.eq.'d'.or.next.eq.'D') next='e'
if (next.eq.','.or.next.eq.'/') next=' '
else
next=' '
endif
if(next.eq.'*') then
if(ic.eq.0.and.iv.gt.0.and.sgn.gt.0) then
c number of values
nv=iv
ic=1
c mantissa sign
if(str(i1+1:i1+1).eq.'-') then
sgn=-1
i1=i1+1
elseif(str(i1+1:i1+1).eq.'+') then
sgn=1
i1=i1+1
else
sgn=1
endif
else
goto 100
endif
elseif(next.eq.'.') then
c end of mantissa's interger part
if(ic.le.1) then
c(1)=iv
ic=2
else
goto 100
endif
elseif(next.eq.'e') then
c end of mantissa
if(ic.eq.3.or.ic.eq.2) then
c(2)=iv
c(3)=i1-i
elseif(ic.le.1) then
c(1)=iv
else
goto 100
endif
ic=4
if(i1+1.gt.ls) goto 100
if(str(i1+1:i1+1).eq.'-') then
expsgn=-1
i1=i1+1
elseif(str(i1+1:i1+1).eq.'+') then
expsgn=1
i1=i1+1
else
expsgn=1
endif
elseif(next.eq.' ') then
c end of number definition
if(ic.eq.4) then
c(4)=iv
elseif(ic.eq.3.or.ic.eq.2) then
c(2)=iv
c(3)=i1-i
elseif(ic.le.1) then
c(1)=iv
else
goto 100
endif
goto 20
else
goto 100
endif
i=i1+1
goto 10
20 continue
ir=i1
v=sgn*(c(1)+c(2)*10.0d0**(-c(3)))*10.0d0**(expsgn*c(4))
return
100 ierr=2
return
end
subroutine s2int(str,nlz,v,ir,ierr)
c if the first characters of str contain representation of a integer >0
c s2int returns
c in v the integer value,
c in nlz the number of leading zeros
c in ir the first unsued character in str
c else
c s2int returns ierr=1 and v=0 and nlz=0
c
character*(*) str
character*1 si
integer ls,nlz,v,ir,ierr
logical first
c
ierr=0
ls=len(str)
c
i=0
v=0
nlz=0
first=.true.
10 i=i+1
if(i.gt.ls) goto 20
si=str(i:i)
if(si.eq.'0') then
if(first) then
nlz=nlz+1
else
v=10*v
endif
else
first=.false.
if(si.eq.'1') then
v=10*v+1
elseif(si.eq.'2') then
v=10*v+2
elseif(si.eq.'3') then
v=10*v+3
elseif(si.eq.'4') then
v=10*v+4
elseif(si.eq.'5') then
v=10*v+5
elseif(si.eq.'6') then
v=10*v+6
elseif(si.eq.'7') then
v=10*v+7
elseif(si.eq.'8') then
v=10*v+8
elseif(si.eq.'9') then
v=10*v+9
else
if(i.eq.1) then
ierr=1
v=0
nlz=0
endif
ir=i
return
endif
endif
goto 10
20 continue
ir=i
return
end
|
