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|
subroutine macro
c
c Copyright INRIA
include '../stack.h'
c
parameter (nz2=nsiz-2,nz3=nsiz-3)
double precision val
integer eol
logical eqid,ptover,vargin,vargout,exec
integer blank,r,ival(2),ptr,top1,count,iadr
integer varargin(nsiz),varargout(nsiz)
equivalence (ival(1),val)
data blank/40/,eol/99/
data varargin/169544223,387059739,nz2*673720360/
data varargout/169544223,504893467,673720349,nz3*673720360/
c
c
iadr(l)=l+l-1
c
r=rstk(pt)
if (ddt .eq. 4) then
write(buf(1:18),'(2i4,i6)') pt,r,fin
call basout(io,wte,' macro pt:'//buf(1:4)//' rstk(pt):'//
& buf(5:8)//' fin:'//buf(9:14))
endif
c
ir=r/100
if(ir.ne.5) goto 10
goto(40,40,60),r-500
goto 99
c
10 continue
if(r.eq.701.or.r.eq.902.or.r.eq.604) goto 50
c initialisation de l'execution d'une macro
c----------------------------------------------
c
ilk=iadr(fin)
c
if(istk(ilk).eq.10) then
c an execstr
exec=.false.
mrhs=0
rhs=0
mlhs=0
l=ilk+5+istk(ilk+1)*istk(ilk+2)
lf=l+istk(ilk+4+istk(ilk+1)*istk(ilk+2))-1
last=isiz-4
if(macr.ne.0.or.paus.ne.0) then
k=lpt(1)-(13+nsiz)
last=lin(k+5)
endif
else
c a macro
exec=rstk(pt).eq.909.or.rstk(pt).eq.903
wmac=0
if(nmacs.gt.0) then
do 15 im=1,nmacs
if(eqid(ids(1,pt),macnms(1,im))) then
wmac=im
goto 16
endif
15 continue
16 continue
endif
l=ilk+1
if(exec) then
vargout=.false.
last=bbot
if(macr.gt.0.or.paus.gt.0) then
k=lpt(1) - (13+nsiz)
last=lin(k+5)
endif
mlhs=istk(l)
l=l + nsiz*mlhs + 1
mrhs=istk(l)
l=l+1
l = l + nsiz*mrhs + 1
rhs=0
lhs=0
goto 17
c . exec(macro)
endif
mrhs=0
last=bot
c set output variable name
mlhs=istk(l)
l0=l
l=l+nsiz*mlhs+1
vargout=.false.
if(mlhs.gt.0) vargout=eqid(istk(l-nsiz),varargout)
if(mlhs.lt.lhs.and..not.vargout) then
if(mlhs.ne.0.or.lhs.gt.1) then
lhs=mlhs
pstk(pt)=l0+1
call error(59)
return
endif
endif
c set input variable name
mrhs=istk(l)
l=l+1
l1=l+nsiz*(rhs-1)
l = l + nsiz*mrhs + 1
lf= l+istk(l-1)+1
if(mrhs.eq.0.and.rhs.le.1) then
if(comp(1).eq.0.and.rhs.eq.1) top=top-1
rhs=0
endif
vargin=.false.
if(mrhs.gt.0) vargin=eqid(istk(l-nsiz-1),varargin)
if(mrhs.lt.rhs.and..not.vargin) then
pstk(pt)=l1-(rhs-1)*nsiz
rhs=mrhs
call error(58)
return
endif
endif
c save line pointers
17 k = lpt(6)
if(k+13+nsiz.gt.lsiz) then
call error(108)
return
endif
lin(k+1) = lpt(1)
lin(k+2) = lpt(2)
lin(k+3) = lpt(3)
lin(k+4) = lpt(4)
lin(k+5) = last
lin(k+6) = ilk
lin(k+7) = l
val = stk(lstk(isiz))
lin(k+8) = ival(1)
lin(k+9) = ival(2)
lin(k+10)=char1
lin(k+11)=sym
call putid(lin(k+12),syn)
lin(k+12+nsiz)=lct(8)
lpt(1) = k + 13+nsiz
c
if ( ptover(1,psiz-1)) return
ids(1,pt) = rhs
ids(2,pt) = lhs
ids(3,pt)=lf
if(vargout) then
ids(4,pt)=1
else
ids(4,pt)=0
endif
pstk(pt)=lct(4)
c
macr=macr+1
c set line pointers
k=lpt(1)
lin(k) = eol
lpt(6) = k
lpt(4) = lpt(1)
lpt(3) = lpt(1)
lpt(2) = lpt(1)
c c_ex lct(1) = 0
if(.not.exec) then
if (ddt .ne. 2) lct(4)=-1
else
lct(4)=pstk(pt-1)
endif
char1 = blank
lin(lpt(4)+1)=blank
c
c save input variables
c next line should be suppressed, but when no arg given rhs is -1
c and not 0
irhs=max(rhs,0)
if(comp(1).eq.0.and..not.exec) then
if( mrhs.gt.0) then
if(vargin.and.irhs.ge.mrhs-1) then
call mklist(irhs-mrhs+1)
irhs=mrhs
l1=l-nsiz-1
endif
mrhs=irhs
rhs=0
do 20 j=1,mrhs
if(infstk(top).ne.1) then
call stackp(istk(l1),0)
else
call stackp(idstk(1,top),0)
endif
l1=l1-nsiz
20 continue
endif
if(vargout) then
call mklist(0)
call stackp(varargout,0)
endif
endif
c
toperr=top
if(istk(ilk).eq.13) then
lct(8)=1
rstk(pt)=501
c next line for forced rhs
ids(5,pt)=0
icall=6
c *call* run
else
lct(8)=1
rstk(pt)=502
c pstk(pt)=0
icall=7
c *call* parse
endif
go to 99
c
40 continue
c fin de l'execution d'une macro
c-----------------------------------
c handle errcatch
if(errct.ne.0.and.errpt.ge.pt.and.rstk(pt-1).ne.903) then
errct=0
errpt=0
err1=0
err2=0
endif
exec=rstk(pt-1).eq.909.or.rstk(pt-1).eq.903
c restaure pointers
k = lpt(1) - (13+nsiz)
ilk=lin(k+6)
char1=lin(k+10)
sym=lin(k+11)
call putid(syn,lin(k+12))
c
lhsr=lhs
c
rhs=ids(1,pt)
lhs=ids(2,pt)
lct(4)=pstk(pt)
vargout=ids(4,pt).eq.1
c
if(comp(1).ne.0) then
comp(2)=comp(1)
comp(1)=0
macr=macr-1
goto 47
endif
if(istk(ilk).ne.10.and..not.exec) then
c recopie des variables de sorties en haut de la pile
l0=ilk+1
c set output variable name
mlhs=istk(l0)
if(mlhs.eq.0.and.lhs.le.1) lhs=0
if(vargout.and.lhs.ge.mlhs) then
lhs1=mlhs-1
else
lhs1=lhs
endif
l0=l0+1
if(lhs1.gt.0) then
mrhs=rhs
rhs=0
do 41 i=1,lhs1
fin=0
call stackg(istk(l0))
if(fin.eq.0) then
call putid(ids(1,pt+1),istk(l0))
call error(4)
if(err.gt.0) return
endif
l0=l0+nsiz
41 continue
rhs=mrhs
endif
if(lhs1.lt.lhs) then
c extract required output variables out of varargout
nv=lhs-mlhs+1
call stackgl(istk(l0),nv)
if(err.gt.0) return
l0=l0+nsiz
endif
endif
c
macr=macr-1
if(istk(ilk).eq.10.or.exec) goto 48
bot=lin(k+5)
if(lhsr.ne.0) then
c gestion des variables retournees par resume
lpt(1)=lin(k+1)
top1=top
top=top-lhs
count=0
c
if(rstk(pt).eq.501) then
c dans les macros compilees
count=pstk(pt+2)
lc=ids(1,pt+1)+1
c . preserve names stored in the macro if macro is moved
if(pt+lhsr.gt.psiz) then
call error(26)
return
endif
do 43 i=1,lhsr
call putid(ids(1,pt+i),istk(lc))
lc=lc+nsiz+1
c . next line to skip print opcode (test for compatibility)
if(istk(lc-1).eq.22) lc=lc+2
43 continue
do 44 i=1,lhsr
call stackp(ids(1,pt+i),0)
if(err.gt.0) return
44 continue
else
c dans les macros non compilees
ptr=pstk(pt+1)
count=pstk(pt+2)
do 45 i=1,lhsr
call stackp(ids(1,ptr),0)
if(err.gt.0) return
ptr=ptr-1
45 continue
endif
c
c on depile les variables relatives au for ou select eventuels
top=top-count
c
if(lhs.gt.0) then
c remise en place des variables de sorties la macros
top1=top1-lhs
do 46 i=1,lhs
top1=top1+1
top=top+1
call unsfdcopy(lstk(top1+1)-lstk(top1),stk(lstk(top1)),1,
1 stk(lstk(top)),1)
lstk(top+1)=lstk(top)+lstk(top1+1)-lstk(top1)
46 continue
endif
endif
c
47 continue
if(lhs.eq.0) then
top=top+1
il=iadr(lstk(top))
istk(il)=0
lstk(top+1)=lstk(top)+1
endif
48 pt=pt-1
lct(8)=lin(k+12+nsiz)
lpt(1)=lin(k+1)
lpt(2)=lin(k+2)
lpt(3)=lin(k+3)
lpt(4)=lin(k+4)
lpt(6)=k
ival(1)=lin(k+8)
ival(2)=lin(k+9)
stk(lstk(isiz))=val
return
c
c exec
50 continue
k = lpt(6)
if(k+13+nsiz.gt.lsiz) then
call error(26)
return
endif
lin(k+1) = lpt(1)
lin(k+2) = lpt(2)
lin(k+3) = lpt(3)
lin(k+4) = lpt(4)
lin(k+5) = isiz-4
c two following lines set information necessary for stackp to know
c current macro context
if(macr.ge.1) lin(k+5)=lin(lpt(1)-(8+nsiz))
if(rio.eq.rte) lin(k+5)=bot
lin(k+6) = lct(4)
c following lines allows to distinguish between macro (<>0) and
c exec (=0)
lin(k+7)=0
c
lin(k+10)=char1
lin(k+11)=sym
lin(k+12+nsiz)=lct(8)
lpt(1) = k + (13+nsiz)
if(lct(4).le.-10) fin=-lct(4)-11
lct(4) = fin
if(rio.eq.rte) paus=paus+1
sym = eol
if ( ptover(1,psiz)) return
lct(8)=0
rstk(pt)=503
pstk(pt)=wmac
wmac=0
icall=7
c *call parse*
go to 99
c
c fin exec
60 continue
k = lpt(1) - (13+nsiz)
lpt(1) = lin(k+1)
lpt(2) = lin(k+2)
lpt(3) = lin(k+3)
lpt(4) = lin(k+4)
lct(4) = lin(k+6)
lpt(6) = k
char1=lin(k+10)
sym=lin(k+11)
lct(8)=lin(k+12+nsiz)
if(rio.eq.rte.and.paus.gt.0) then
bot=lin(k+5)
paus=paus-1
endif
wmac=pstk(pt)
pt=pt-1
go to 99
c
99 continue
return
end
|
