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// Scilab ( http://www.scilab.org/ ) - This file is part of Scilab
// Copyright (C) INRIA -
//
// This file must be used under the terms of the CeCILL.
// This source file is licensed as described in the file COPYING, which
// you should have received as part of this distribution. The terms
// are also available at
// http://www.cecill.info/licences/Licence_CeCILL_V2-en.txt
function [y,x]=csim(u,dt,sl,x0,tol)
//Syntax:
// [y [,x]]=csim(u,dt,sl,[x0])
// simulation of the controlled linear system sl.
// sl is assumed to be a continuous-time system.
// u is the control and x0 the initial state.
//
//u can be:
// - a function
// [inputs]=u(t)
// - a list
// list(ut,parameter1,....,parametern) such that
// inputs=ut(t,parameter1,....,parametern)
// - the character string 'impuls' for impulse response calculation
// (here sl is assumed SISO without direct feedthrough and x0=0)
// - the character string 'step' for step response calculation
// (here sl is assumed SISO without direct feedthrough and x0=0)
//dt is a vector of instants with dt(1) = initial time
// that is: x0=x
// dt(1)
//
//y matrix such that:
// y=[y y ... y ]
// dt(1) dt(2) dt(n)
//x matrix such that:
// x=[x x ... x ]
// dt(1) dt(2) dt(n)
//
//See also:
// dsimul flts ltitr rtitr ode impl
//!
[lhs,rhs]=argn(0)
//
if rhs<3 then error(39),end
sltyp=typeof(sl)
if and(sltyp<>['state-space' 'rational']) then
error(msprintf(_("%s: Wrong type for input argument #%d: %s data structure expected.\n"),"csim",3,"syslin"))
end
if sltyp=='rational' then sl=tf2ss(sl),end
if sl.dt<>'c' then
warning(msprintf(gettext("%s: Input argument %d is assumed continuous time.\n"),"csim",1));
end
//
[a,b,c,d]=sl(2:5);
if type(d)==2°ree(d)>0 then
d=coeff(d,0);
warning(msprintf(gettext("%s: Direct feedthrough set to its zero degree coefficient.\n"),"csim"));
end
[ma,mb]=size(b);
//
imp=0;step=0
text='if t==0 then y=0, else y=1,end'
//
select type(u)
case 10 then //input given by its type (step or impuls)
if mb<>1 then error(95,1);end;
if part(u,1)=='i' then
//impuse response
imp=1;
if norm(d,1)<>0 then
warning(msprintf(gettext("%s: Direct feedthrough set to zero.\n"),"csim"));
d=0*d;
end;
elseif part(u,1)=='s' then
step=1
if norm(d,1)<>0 then
warning(msprintf(gettext("%s: Direct feedthrough set to zero.\n"),"csim"));
d=0*d;
end;
else
error(msprintf(gettext("%s: Wrong value for input argument #%d: Must be in the set {%s}.\n"),"csim",1,"""step"",""impuls"""))
end;
deff('[y]=u(t)',text);
case 11 then //input given by a function of time
comp(u)
case 13 then //input given by a function of time
case 1 then //input given by a vector of data
[mbu,ntu]=size(u);
if mbu<>mb | ntu<>size(dt,'*') then
error(msprintf(gettext("%s: Incompatible input arguments #%d and #%d: Same column dimensions expected.\n"),"csim",1,2))
end
case 15 then //input given by a list: function of time with parameters
uu=u(1),
if type(uu)==11 then
comp(uu),
u(1)=uu,
end
else error(44,2)
end;
//
if rhs==3 then x0=sl(6),end
if imp==1|step==1 then x0=0*x0,end
nt=size(dt,'*');x=0*ones(ma,nt)
[a,v]=balanc(a);
v1=v;//save for backward transformation
//apply transformation u without matrix inversion
[k,l]=find(v<>0) //get the permutation
//apply right transformation
v=v(k,l);//diagonal matrix
c=c(:,k)*v;
//apply left transformation
v=diag(1 ./diag(v));b=v*b(k,:);x0=v*x0(k)
[a,v2,bs]=bdiag(a,1);b=v2\b;c=c*v2;x0=v2\x0;
//form the differential equation function
if type(u)==1 then
//form a continuuous time interpolation of the given data
ut=u;
if min(size(ut))==1 then ut=matrix(ut,1,-1),end
deff('[y]=u(t)',['ind=find(dt<=t);nn=ind($)'
'if (t==dt(nn)|nn==nt) then '
' y=ut(:,nn)'
'else '
' y=ut(:,nn)+(t-dt(nn))/(dt(nn+1)-dt(nn))*(ut(:,nn+1)-ut(:,nn))'
'end']);
deff('[ydot]=%sim2(%tt,%y)','ydot=ak*%y+bk*u(%tt)');
elseif type(u)<>15 then
deff('[ydot]=%sim2(%tt,%y)','ydot=ak*%y+bk*u(%tt)');
ut=ones(mb,nt);for k=1:nt, ut(:,k)=u(dt(k)),end
else
%sim2=u
tx=' ';for l=2:size(u), tx=tx+',%'+string(l-1);end;
deff('[ydot]=sk(%tt,%y,u'+tx+')','ydot=ak*%y+bk*u(%tt'+tx+')');
%sim2(0)=sk;u=u(1)
deff('[ut]=uu(t)',...
['['+part(tx,3:length(tx))+']=%sim2(3:'+string(size(%sim2))+')';
'ut=ones(mb,nt);for k=1:nt, ut(:,k)=u(t(k)'+tx+'),end'])
ut=uu(dt);
end;
//simulation
k=1;
for n=bs',
kk=k:k+n-1
ak=a(kk,kk)
bk=b(kk,:)
nrmu=maxi([norm(bk*ut,1),norm(x0(kk))])
if nrmu > 0 then
if rhs<5 then
atol=1.d-12*nrmu;rtol=atol/100
else
atol=tol(1);rtol=tol(2)
end
x(kk,:)=ode('adams',x0(kk),dt(1),dt,rtol,atol,%sim2)
if imp==1 then x(kk,:)=ak*x(kk,:)+bk*ut,end
end;
k=k+n
end;
if imp==0&step==0 then y=c*x+d*ut,else y=c*x,end
if lhs==2 then x=v1*v2*x,end
endfunction
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