File: intersect.sci

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// Scilab ( http://www.scilab.org/ ) - This file is part of Scilab
// Copyright (C) INRIA
// 
// This file must be used under the terms of the CeCILL.
// This source file is licensed as described in the file COPYING, which
// you should have received as part of this distribution.  The terms
// are also available at
// http://www.cecill.info/licences/Licence_CeCILL_V2-en.txt

function [x_out,ka_out,kb_out]=intersect(a_in,b_in,orient)
// returns the vector of common values of two vectors
// Author : Serge Steer INRIA
  if ( (a_in == [])| (b_in == []) ) then 
    x_out=[];
    ka_out=[];
    kb_out=[];
    return
  end
  if argn(2)<3 then
    //remove duplicate values in a_in and b_in
    [a,ka]=unique(matrix(a_in,1,-1));
    
    [b,kb]=unique(matrix(b_in,1,-1));
    kab=[ka, -kb];
    //find duplicated values in [a_in,b_in], 
    [x,ksort] = gsort([a,b],'g','i'); //sort the array
    
    kab = kab(ksort);//apply [a_in,b_in] sorting permutation to kab
    keq = find( x(2:$) == x(1:$-1) ); // find consecutive equal values index
    
    
    if keq == [] then 
      //the intersection is empty
      x_out = [];
      ka_out = [];
      kb_out = [];
    else
      x_out =x(keq); //the intersection values in increasing order
      
      if argn(1)>1 then //build the output index
	
	// each duplicated value appear twice  and only twice and in
	// consecutive positions keq(i) and keq(i)+1 in the sorted array x
	kab=kab([keq keq+1]);
	
	//the positive values correspond to a_in index while the negative to b_in index.
	ka_out = kab(kab>0); //select index of intersection elements in a_in
	kb_out = -kab(kab<0); //select index of intersection elements in b_in

	//insure that a_in(ka_out)==x_out and b_in(kb_out)==x_out.
	//I was'nt able to find a simple way.
	[s,k]=gsort(a_in(ka_out),'g','i'); ka_out=ka_out(k)
	[s,k]=gsort(b_in(kb_out),'g','i'); kb_out=kb_out(k)
      end
    end
  elseif  orient==1|orient=="r" then
    //remove duplicate rows in a_in and b_in
    [a,ka]=unique(a_in,"r");
    
    [b,kb]=unique(b_in,"r");
    kab=[ka; -kb];
    //find duplicated rows in [a_in;b_in], 
    
    [x,ksort] = gsort([a;b],'lr','i'); //sort the rows
    
    kab = kab(ksort);//apply [a_in,b_in] sorting permutation to kab
    keq = find(and(x(2:$,:) == x(1:$-1,:),'c')) // find index of consecutive equal values 
    
    if keq == [] then 
      //the intersection is empty
      x_out = [];
      ka_out = [];
      kb_out = [];
    else
      x_out =x(keq,:); //the intersection values in increasing order
      
      if argn(1)>1 then //build the output index
	
	// each duplicated value appear twice  and only twice and in
	// consecutive positions keq(i) and keq(i)+1 in the sorted array x
	kab=kab([keq keq+1]);
	
	//the positive values correspond to a_in index while the negative to b_in index.
	ka_out = kab(kab>0); //select index of intersection elements in a_in
	kb_out = -kab(kab<0); //select index of intersection elements in b_in

	//insure that a_in(ka_out,:)==x_out and b_in(kb_out,:)==x_out.
	//I was'nt able to find a simple way.
	[s,k]=gsort(a_in(ka_out,:),'lr','i'); ka_out=ka_out(k)
	[s,k]=gsort(b_in(kb_out,:),'lr','i'); kb_out=kb_out(k)
	
	
      end
    end
  elseif  orient==2|orient=="c" then
    //remove duplicate columns in a_in and b_in
    [a,ka]=unique(a_in,"c");
    
    [b,kb]=unique(b_in,"c");
    kab=[ka, -kb];
    //find duplicated rows in [a_in;b_in], 
    [x,ksort] = gsort([a b],'lc','i'); //sort the rows
    
    kab = kab(ksort);//apply [a_in,b_in] sorting permutation to kab
    keq = find(and(x(:,2:$) == x(:,1:$-1),'r')) // find index of consecutive equal values 
    
    if keq == [] then 
      //the intersection is empty
      x_out = [];
      ka_out = [];
      kb_out = [];
    else
      x_out =x(:,keq); //the intersection values in increasing order
      
      if argn(1)>1 then //build the output index
	
	// each duplicated value appear twice  and only twice and in
	// consecutive positions keq(i) and keq(i)+1 in the sorted array x
	kab=kab([keq keq+1]);
	
	//the positive values correspond to a_in index while the negative to b_in index.
	ka_out = kab(kab>0); //select index of intersection elements in a_in
	kb_out = -kab(kab<0); //select index of intersection elements in b_in

	//insure that a_in(ka_out,:)==x_out and b_in(kb_out,:)==x_out.
	//I was'nt able to find a simple way.
	[s,k]=gsort(a_in(:,ka_out),'lc','i'); ka_out=ka_out(k)
	[s,k]=gsort(b_in(:,kb_out),'lc','i'); kb_out=kb_out(k)
      end
    end
	
  else
     error(msprintf(gettext("%s: Wrong value for input argument #%d: %d,''%s'',%d or ''%s'' expected\n"),'intersect',3,1,"r",2,"c"));
  end
  
endfunction