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signature S =
sig
datatype t = A | B of t
end
signature X =
sig
structure S : S
structure T : S
sharing S = T
end
(*
2011-11-25 katsu
This causes an unexpected sigature mismatch error.
145_sharing.sml:9.3-9.15 Error:
(name evaluation Sig-050) Signature mismatch in sharing type clause:T.t
*)
(*
2011-11-25 ohori
Fixed.
For sharing types, we need to check the consistency of datatype constructor.
This is something beyond the semantics defined in the Definition, since we
need to generate a structure instantce for functor.
To do this, type equality checking must be performed under the assumption that
all type ids specified in sharing types are equivalent. This mechanism is added.
*)
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