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Dense example problem:
Robertson kinetics, NEQ = 3
At t = 0.2639E+00 y = 0.989965E+00 0.347056E-04 0.100000E-01
Above is a root, INFO() = 0 1
At t = 0.4000E+00 y = 0.985165E+00 0.338627E-04 0.148011E-01
At t = 0.4000E+01 y = 0.905528E+00 0.224062E-04 0.944493E-01
At t = 0.4000E+02 y = 0.715866E+00 0.918722E-05 0.284125E+00
At t = 0.4000E+03 y = 0.450547E+00 0.322302E-05 0.549450E+00
At t = 0.4000E+04 y = 0.183226E+00 0.894390E-06 0.816773E+00
At t = 0.4000E+05 y = 0.389863E-01 0.162191E-06 0.961014E+00
At t = 0.4000E+06 y = 0.493403E-02 0.198330E-07 0.995066E+00
At t = 0.4000E+07 y = 0.516524E-03 0.206719E-08 0.999483E+00
At t = 0.1980E+08 y = 0.100000E-03 0.400071E-09 0.999900E+00
Above is a root, INFO() = -1 0
At t = 0.4000E+08 y = 0.477176E-04 0.190880E-09 0.999952E+00
At t = 0.4000E+09 y = 0.360970E-05 0.144391E-10 0.999996E+00
At t = 0.4000E+10 y = 0.889920E-06 0.355968E-11 0.999999E+00
At t = 0.4000E+11 y = 0.635210E-07 0.254084E-12 0.100000E+01
Final value of ydot = -0.115031E-17 -0.460125E-23 0.272393E-17
Final statistics:
No. steps = 399 No. f-s = 567 No. J-s = 12 No. LU-s = 98
No. nonlinear iterations = 564
No. nonlinear convergence failures = 2
No. error test failures = 15
No. root function evals = 429
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