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fidaRoberts_dns: Robertson kinetics DAE serial exampleproblem for IDA
Three equation chemicalkinetics problem.
Tolerance parameters: rtol = 0.10E-03 atol = 0.10E-05 0.10E-09 0.10E-05
Initial conditions y0 = ( 0.10E+01 0.00E+00 0.00E+00)
t y1 y2 y3 nst k h
0.2640E+00 0.9900E+00 0.3471E-04 0.1000E-01 75 2 0.5716E-01
Above is a root, INFO() = 0 1
0.4000E+00 0.9852E+00 0.3386E-04 0.1480E-01 77 3 0.1143E+00
0.4000E+01 0.9055E+00 0.2240E-04 0.9447E-01 91 4 0.3704E+00
0.4000E+02 0.7158E+00 0.9185E-05 0.2842E+00 127 4 0.2963E+01
0.4000E+03 0.4505E+00 0.3223E-05 0.5495E+00 177 3 0.1241E+02
0.4000E+04 0.1832E+00 0.8940E-06 0.8168E+00 228 3 0.2765E+03
0.4000E+05 0.3899E-01 0.1622E-06 0.9610E+00 278 5 0.2614E+04
0.4000E+06 0.4939E-02 0.1985E-07 0.9951E+00 324 5 0.2770E+05
0.4000E+07 0.5176E-03 0.2072E-08 0.9995E+00 355 4 0.3979E+06
0.2075E+08 0.1000E-03 0.4000E-09 0.9999E+00 374 4 0.1592E+07
Above is a root, INFO() = -1 0
0.4000E+08 0.5191E-04 0.2076E-09 0.9999E+00 380 3 0.6366E+07
0.4000E+09 0.5882E-05 0.2353E-10 0.1000E+01 394 1 0.9167E+08
0.4000E+10 0.7054E-06 0.2822E-11 0.1000E+01 402 1 0.1467E+10
0.4000E+11 -0.7300E-06 -0.2920E-11 0.1000E+01 407 1 0.2347E+11
Final Run Statistics:
Number of steps = 407
Number of residual evaluations = 557
Number of Jacobian evaluations = 65
Number of nonlinear iterations = 557
Number of error test failures = 6
Number of nonlinear conv. failures = 0
Number of root function evals. = 445
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