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/* Fast hashing routine for a long.
(C) 2002 William Lee Irwin III, IBM */
/*
* Knuth recommends primes in approximately golden ratio to the maximum
* integer representable by a machine word for multiplicative hashing.
* Chuck Lever verified the effectiveness of this technique:
* http://www.citi.umich.edu/techreports/reports/citi-tr-00-1.pdf
*
* These primes are chosen to be bit-sparse, that is operations on
* them can use shifts and additions instead of multiplications for
* machines where multiplications are slow.
*/
#if BITS_PER_LONG == 32
/* 2^31 + 2^29 - 2^25 + 2^22 - 2^19 - 2^16 + 1 */
#define GOLDEN_RATIO_PRIME 0x9e370001UL
#elif BITS_PER_LONG == 64
/* 2^63 + 2^61 - 2^57 + 2^54 - 2^51 - 2^18 + 1 */
#define GOLDEN_RATIO_PRIME 0x9e37fffffffc0001UL
#else
#error Define GOLDEN_RATIO_PRIME for your wordsize.
#endif
static inline unsigned long hash_long(unsigned long val, unsigned int bits)
{
unsigned long hash = val;
#if BITS_PER_LONG == 64
/* Sigh, gcc can't optimise this alone like it does for 32 bits. */
unsigned long n = hash;
n <<= 18;
hash -= n;
n <<= 33;
hash -= n;
n <<= 3;
hash += n;
n <<= 3;
hash -= n;
n <<= 4;
hash += n;
n <<= 2;
hash += n;
#else
/* On some cpus multiply is faster, on others gcc will do shifts */
hash *= GOLDEN_RATIO_PRIME;
#endif
/* High bits are more random, so use them. */
return hash >> (BITS_PER_LONG - bits);
}
static inline unsigned long hash_ptr(void *ptr, unsigned int bits)
{
return hash_long((unsigned long)ptr, bits);
}
static inline unsigned long hash_str(char *name, int bits)
{
unsigned long hash = 0;
unsigned long l = 0;
int len = 0;
unsigned char c;
do {
if (!(c = *name++)) {
c = (char)len; len = -1;
}
l = (l << 8) | c;
len++;
if ((len & (BITS_PER_LONG/8-1))==0)
hash = hash_long(hash^l, BITS_PER_LONG);
} while (len);
return hash >> (BITS_PER_LONG - bits);
}
static inline unsigned long hash_mem(char *buf, int length, int bits)
{
unsigned long hash = 0;
unsigned long l = 0;
int len = 0;
unsigned char c;
do {
if (len == length) {
c = (char)len; len = -1;
} else
c = *buf++;
l = (l << 8) | c;
len++;
if ((len & (BITS_PER_LONG/8-1))==0)
hash = hash_long(hash^l, BITS_PER_LONG);
} while (len);
return hash >> (BITS_PER_LONG - bits);
}
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