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##############################################################################
#
# Copyright (c) 2002, 2003 Zope Corporation and Contributors.
# All Rights Reserved.
#
# This software is subject to the provisions of the Zope Public License,
# Version 2.1 (ZPL). A copy of the ZPL should accompany this distribution.
# THIS SOFTWARE IS PROVIDED "AS IS" AND ANY AND ALL EXPRESS OR IMPLIED
# WARRANTIES ARE DISCLAIMED, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
# WARRANTIES OF TITLE, MERCHANTABILITY, AGAINST INFRINGEMENT, AND FITNESS
# FOR A PARTICULAR PURPOSE.
#
##############################################################################
"""urlparse-like helpers that normalize file: URLs.
ZConfig and urllib2 expect file: URLs to consistently use the '//'
hostpart seperator; the functions here enforce this constraint.
"""
import urlparse as _urlparse
try:
from urlparse import urlsplit
except ImportError:
def urlsplit(url):
# Check for the fragment here, since Python 2.1.3 didn't get
# it right for things like "http://www.python.org#frag".
if '#' in url:
url, fragment = url.split('#', 1)
else:
fragment = ''
parts = list(_urlparse.urlparse(url))
parts[-1] = fragment
param = parts.pop(3)
if param:
parts[2] += ";" + param
return tuple(parts)
def urlnormalize(url):
lc = url.lower()
if lc.startswith("file:/") and not lc.startswith("file:///"):
url = "file://" + url[5:]
return url
def urlunsplit(parts):
parts = list(parts)
parts.insert(3, '')
url = _urlparse.urlunparse(tuple(parts))
if (parts[0] == "file"
and url.startswith("file:/")
and not url.startswith("file:///")):
url = "file://" + url[5:]
return url
def urldefrag(url):
url, fragment = _urlparse.urldefrag(url)
return urlnormalize(url), fragment
def urljoin(base, relurl):
url = _urlparse.urljoin(base, relurl)
if url.startswith("file:/") and not url.startswith("file:///"):
url = "file://" + url[5:]
return url
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