std::unordered_set::begin, std::unordered_set::cbegin
From cppreference.com
< cpp | container | unordered set
iterator begin(); |
(since C++11) | |
const_iterator begin() const; |
(since C++11) | |
const_iterator cbegin() const; |
(since C++11) | |
Returns an iterator to the first element of the container.
If the container is empty, the returned iterator will be equal to end().
Contents |
[edit] Parameters
(none)
[edit] Return value
Iterator to the first element
[edit] Exceptions
noexcept specification:
noexcept
[edit] Complexity
Constant
[edit] Example
Run this code
#include <iostream> #include <unordered_set> struct Point { double x, y; }; int main() { Point pts[3] = { {1, 0}, {2, 0}, {3, 0} }; //points is a set containing the addresses of points std::unordered_set<Point *> points = { pts, pts + 1, pts + 2 }; //Change each y-coordinate of (i, 0) from 0 into i^2 and print the point for(auto iter = points.begin(); iter != points.end(); ++iter){ (*iter)->y = ((*iter)->x) * ((*iter)->x); //iter is a pointer-to-Point* std::cout << "(" << (*iter)->x << ", " << (*iter)->y << ") "; } std::cout << '\n'; //Now using the range-based for loop, we increase each y-coordinate by 10 for(Point * i : points) { i->y += 10; std::cout << "(" << i->x << ", " << i->y << ") "; } }
Possible output:
(3, 9) (1, 1) (2, 4) (3, 19) (1, 11) (2, 14)
[edit] See also
returns an iterator to the end (public member function) |