1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49
|
% Generated by roxygen2: do not edit by hand
% Please edit documentation in R/noded_with_condition.R
\name{which_node}
\alias{which_node}
\title{Which node id is common to a group of labels}
\usage{
which_node(dend, labels, max_id = TRUE, ...)
}
\arguments{
\item{dend}{a dendrogram dend}
\item{labels}{a character vector of labels from the tree}
\item{max_id}{logical (TRUE) - if to return only the max id}
\item{...}{ignored.}
}
\value{
An integer with the id(s) of the nodes which includes all of the labels.
}
\description{
This function identifies which edge(s) in a tree has group of labels ("tips") in common.
By default it only returns the edge (node) with the heighest id.
}
\examples{
dend <- iris[1:10, -5] \%>\%
dist() \%>\%
hclust() \%>\%
as.dendrogram() \%>\%
set("labels", 1:10)
dend \%>\% plot()
which_node(dend, c(1, 2), max_id = FALSE)
which_node(dend, c(2, 3), max_id = FALSE)
which_node(dend, c(2, 3))
dend \%>\% plot()
the_h <- get_nodes_attr(dend, "height", which_node(dend, c(4, 6)))
the_h
abline(h = the_h, lty = 2, col = 2)
get_nodes_attr(dend, "height", which_node(dend, c(4, 6)))
get_nodes_attr(dend, "members", which_node(dend, c(4, 6)))
}
\seealso{
\link{noded_with_condition}, \link{branches_attr_by_clusters},
\link{nnodes}, \link{branches_attr_by_labels}, \link{get_nodes_attr}
\link[ape]{which.edge}
}
|